First slide

Projection Under uniform Acceleration

Question

A body projected at an angle reaches a maximum height, h. The total time of flight is

Easy

A

4 sec
B

$2 \sqrt{\frac{h}{g}}$
C

$\sqrt{\frac{h}{g}}$
D

$2 \sqrt{\frac{2 h}{g}}$

Solution

$\begin{array}{l} H = \frac{{gT}^{2}}{8} where \\ H = \frac{u^{2} \sin^{2} θ}{2 g} and T = \frac{2 usin θ}{g} \\ \Rightarrow T = \sqrt{\frac{8 H}{g}} \\ = 2 \sqrt{\frac{2 H}{g}} \end{array}$

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