Q.

A body is projected at an angle θ so that its range is maximum. If T is the time of flight then the value of maximum range is (acceleration due to gravity = g)

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a

g2T2

b

gT2

c

gT22

d

g2T22

answer is C.

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Detailed Solution

formax imumrange θ= 450Rmax=u2g when θ=45°,T=2usinθg
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A body is projected at an angle θ so that its range is maximum. If T is the time of flight then the value of maximum range is (acceleration due to gravity = g)