A body is projected at an angle θ so that its range is maximum. If T is the time of flight then the value of maximum range is (acceleration due to gravity = g)

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g2T2

gT2

gT22

g2T22

answer is C.

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Detailed Solution

formax imumrange θ= 450Rmax=u2g when θ=45°,T=2usinθg

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