First slide

Projection Under uniform Acceleration

Question

A body projected at an angle with the horizontal has a range 300 m. If the time of flight is 6 s, then the horizontal component of velocity is

Easy

A

30 ms^-1
B

50 ms^-1
C

40 ms^-1
D

45 ms^-1

Solution

Horizontal range, R = u cos $θ$ T
Given that R = 300 m, T = 6 sec.
Therefore, horizontal component of velocity,
$ucos θ = \frac{R}{T} = \frac{300}{6} = 50 {ms}^{- 1}$
Hence, correct answer is (2).

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