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Questions  

A body is projected at an angle α with horizontal. It crosses a horizontal line above the point of projection during its upward journey making an angle of  θ=45o with horizontal. If velocity of projection is 20 m/s, and α=60o,  find the height of the line above the point of projection.

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a
10 2 m
b
10 m
c
10 3 m
d
20 m

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detailed solution

Correct option is B

Vcos450 =  20 cos600  ⇒   V=102  m/s.∴     Vsin4502 = usinα2−2gh. 2gh=u2sin2α−V2sin245         =400×34−200×12∴h=10 m


Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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