Questions
A body is projected at an angle with horizontal. It crosses a horizontal line above the point of projection during its upward journey making an angle of with horizontal. If velocity of projection is 20 m/s, and find the height of the line above the point of projection.
detailed solution
Correct option is B
Vcos450 = 20 cos600 ⇒ V=102 m/s.∴ Vsin4502 = usinα2−2gh. 2gh=u2sin2α−V2sin245 =400×34−200×12∴h=10 mSimilar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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