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Q.

A body is projected at an angle α with horizontal. It crosses a horizontal line above the point of projection during its upward journey making an angle of  θ=45o with horizontal. If velocity of projection is 20 m/s, and α=60o,  find the height of the line above the point of projection.

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a

10 2 m

b

10 m

c

10 3 m

d

20 m

answer is B.

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Detailed Solution

Vcos450 =  20 cos600  ⇒   V=102  m/s.∴     Vsin4502 = usinα2−2gh. 2gh=u2sin2α−V2sin245         =400×34−200×12∴h=10 m
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