Projection Under uniform Acceleration

Question

A body is projected at an angle of 30° with the horizontal and with a speed of 30 ms^{-1}. What is the angle with the horizontal after 1.5 s ? (g = 10 ms^{-2})

Easy

Solution

The time of flight is given by

$\mathrm{T}=\frac{2\mathrm{usin}\theta}{\mathrm{g}}=\frac{2\times 30\times 1/2}{10}=3\mathrm{s}$

Thus, after 1.5 s, the body will be at the highest point.

So the direction of motion will be horizontal after 1.5 s, the angle with the horizontal is 0°.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Download Now