A body is projected downwards at an angle of 300 to the horizontal with a velocity of 9.8 m/sec from the top of a tower 29.4 m high. How long will it take before striking the ground?(g=9.9 m/s2)

given initial velocity=u=9.8 m/s; downward angle of projection wrt horizontal=θ=300; tower height=h=29.4m;g=9.8 m/s2vertical component of the velocity=vy=Usin⁡θ=9.8sin⁡30∘; Taking downward as +y-axis:vy=4.9m/sec We know  h=Usin⁡θt+12gt2   ; substitute given values,⇒29.4=4.9t+12(9.8)t2⇒t=2sec=time taken to strike the ground