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A body is projected from ground making an angle with horizontal. Its trajectory is as shown in figure. Average velocity of the particle during its journey from A to B is V1, from C to D is V2 and E to F is V3. Then
detailed solution
Correct option is D
Horizontal component of velocity of the particle remains unchanged. Therefore, V1=V2=V3=ucosα∴ V2=V1+V32Talk to our academic expert!
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A ball is projected obliquely with a velocity 49 ms–1 strikes the ground at a distance of 245 m from the point of projection. It remained in air for
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