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Q.

A body is projected from ground making an angle with horizontal. Its trajectory is as shown in figure. Average velocity of the particle during its journey from A to B is V1, from C to D is V2 and E to F is V3. Then

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a

V1>V2>V3

b

V1

c

V1>V2

d

V2=V1+V32

answer is D.

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Detailed Solution

Horizontal component of velocity of the particle remains unchanged. Therefore, V1=V2=V3=ucosα∴ V2=V1+V32
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A body is projected from ground making an angle with horizontal. Its trajectory is as shown in figure. Average velocity of the particle during its journey from A to B is V1, from C to D is V2 and E to F is V3. Then