First slide

Projection Under uniform Acceleration

Question

A body is projected from ground in uniform gravitational field making an angle with horizontal. If ratio of its maximum potential energy to the minimum kinetic energy is 3, the angle of projection is

Moderate

A

60^o
B

30^o
C

45^o
D

37^o

Solution

$\begin{array}{l} \frac{m g H}{\frac{1}{2} m {(u \cos α)}^{2}} = 3 \\ \Rightarrow \frac{m . g . (u^{2} \sin^{2} α / 2 g)}{\frac{1}{2} m u^{2} \cos^{2} α} = 3 \Rightarrow \tan^{2} α = 3 \Rightarrow α = 60^{o} \end{array}$

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