Questions
A body is projected from ground with a speed of 40 m/s making an angle of 30o with horizontal. The body crosses a horizontal line twice in a time interval . If the height of the line above the ground is 15 m, find . [Take g = 10 m/s2]
detailed solution
Correct option is A
The body crosses the horizontal line PQ with velocity v at A and B ∴ Vsinθ2=usinα2−2.g.h=40sin30o2−2.10.15⇒Vsinθ=10 m/s∴ Δt=2Vsinθg=2×1010sec=2 secTalk to our academic expert!
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