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A body is projected from ground with a velocity $\vec{u} = (40 \hat{i} + 30 \hat{j}) m / s . T h e n i t s r a n g e i s (T a k e g = 10 m / s^{2})$

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detailed solution

Correct option is A

(1)∴ T=2u sinθg= 2 × 3010 sec =6 sec.∴ Range R= 4cos θ ×T=40 × 6m=240 m.

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A body is projected from ground with a velocity u→=40i^+30j^m/s. Then its range is Take g=10 m/s2

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A body is projected from ground with a velocity $\vec{u} = (40 \hat{i} + 30 \hat{j}) m / s . T h e n i t s r a n g e i s (T a k e g = 10 m / s^{2})$