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Q.

A body is projected from ground with a velocity u→=40i^+30j^m/s.   Then  its  range  is  Take g=10 m/s2

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a

240 m

b

280 m

c

200 m

d

120 m

answer is A.

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Detailed Solution

(1)∴   T=2u sinθg= 2 × 3010  sec =6 sec.∴   Range  R= 4cos θ ×T=40 × 6m=240 m.
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