First slide

Projection Under uniform Acceleration

Question

A body is projected from ground with a velocity $\vec{u} = (40 \hat{i} + 30 \hat{j}) m / s . T h e n i t s r a n g e i s (T a k e g = 10 m / s^{2})$

Easy

A

240 m
B

280 m
C

200 m
D

120 m

Solution

(1)
$∴ T = \frac{2 u \sin θ}{g} = \frac{2 \times 30}{10} \sec = 6 \sec .$
$∴ R a n g e R = 4 \cos θ \times T = 40 \times 6 m = 240 m .$

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