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Questions  

A body is projected from ground  with a velocity ‘u’ making an angle of 60o with horizontal. If the body just clears the building in a time interval of 2 sec, maximum height attained by the body is 

a
120 m
b
60 m
c
80 m
d
30 m

detailed solution

Correct option is B

ucosα×Δt=l ⇒ucos60o×2=40⇒u=40 m/s∴ Hmax=u2sin2α2g=402sin260o2×10m=60 m

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