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Q.

A body is projected from ground  with a velocity ‘u’ making an angle of 60o with horizontal. If the body just clears the building in a time interval of 2 sec, maximum height attained by the body is

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a

120 m

b

60 m

c

80 m

d

30 m

answer is B.

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Detailed Solution

ucosα×Δt=l ⇒ucos60o×2=40⇒u=40 m/s∴ Hmax=u2sin2α2g=402sin260o2×10m=60 m
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