Question

A body is projected from the ground with a velocity $v = (3 \hat{i} + 10 \hat{j}) {ms}^{- 1} .$ The maximum height attained and the range of the body respectively are (Take, 9 = 10 ms^-2)

Moderate

Solution

Given, $v = (3 \hat{i} + 10 \hat{j}) {ms}^{- 1}, v_{x} = 3 {ms}^{- 1}, v_{y} = 10 {ms}^{- 1}$
$H = \frac{v_{y}^{2}}{2 g} = \frac{100}{2 \times 10} = 5 m$
$R = v_{x} \times T = v_{x} \times \frac{2 v_{y}}{g} = 6 m$

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