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A body projected from a height 60 m with a velocity 10 m/s at an angle $30^{0}$ above the horizontal. The time of flight of the body is $[g = 10 m / s^{2}]$ ….

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Correct option is D

Initial vertical velocity =10sin300=5m/s(upwords)Displacement of the body is s=60m(downwords)−s=ut−12gt2 −60=5t−12×10×t2 t2−t−12=0 t(t−4)+3(t−4)=0 t=4s

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A body projected from a height 60 m with a velocity 10 m/s at an angle 300 above the horizontal. The time of flight of the body is g=10m/s2 ….

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A body projected from a height 60 m with a velocity 10 m/s at an angle $30^{0}$ above the horizontal. The time of flight of the body is $[g = 10 m / s^{2}]$ ….