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A body is projected from a point on ground with velocity 40 m/s. If the velocity of projection and the velocity with which it strikes the ground are mutually perpendicular, then maximum height attained by the body is
detailed solution
Correct option is D
α+α=90o⇒α=45o∴ Hmax=u2sin2α2g=402sin245o2×10m=40 mTalk to our academic expert!
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