A body is projected from the top of tower with horizontal velocity ‘U’. Let t1 be the time taken by body to reach ground under ideal conditions and t2 be the time to reach the ground when air resistance is considered and is assumed to be constant.
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a
t1≺t2
b
t1≻t2
c
t1=t2
d
t1≥t2
answer is A.
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Detailed Solution
when body is projected horizontally, case 1: in the absence of air , time of flight=t1=2hg case 2: in the presence of air , time of flight=t2=2hg-Rm where R = air resistance; m=mass of the body hence t2>t1