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A body is projected horizontally from a height of 78.4 m with a velocity 10 ms^-1. Its velocity after 3 seconds is : [g = 10 ms^-2] (Take direction of projection on $\vec{i}$ and vertically upward direction on $\vec{j}$ ).

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10i→−30j→

10i→+30j→

20i→−30j→

10i→+103j→

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detailed solution

Correct option is A

ux=u=10ms−1 vx=10ms−1v¯=vxi¯+vyj¯v¯=10i¯−30j¯

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A body is projected horizontally from a height of 78.4 m with a velocity 10 ms-1. Its velocity after 3 seconds is : [g = 10 ms-2] (Take direction of projection on i→ and vertically upward direction on j→).

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A body is projected horizontally from a height of 78.4 m with a velocity 10 ms^-1. Its velocity after 3 seconds is : [g = 10 ms^-2] (Take direction of projection on $\vec{i}$ and vertically upward direction on $\vec{j}$ ).