First slide
Projection Under uniform Acceleration
Question

A body is projected horizontally from a height of 78.4 m with a velocity 10 ms-1. Its velocity after 3 seconds is : [g = 10 ms-2] (Take direction of projection on i and vertically upward direction on j).

Easy
Solution

ux=u=10ms1 vx=10ms1v¯=vxi¯+vyj¯v¯=10i¯30j¯

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