First slide

Projection Under uniform Acceleration

Question

A body is projected horizontally from a height of 78.4 m with a velocity 10 m/s. Then the angle made by its velocity vector with x-axis after 4 seconds is

Moderate

A

Tan^-1(3)
B

Tan^-1(4)
C

Tan^-1(5)
D

Tan^-1(6)

Solution

$\large Tan\theta = \frac{{{V_y}}}{{{V_x}}} = \frac{{gt}}{u} = \frac{{10 \times 4}}{{10}} = 4 \Rightarrow \theta = Ta{n^{ - 1}}(4)$

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