A body is projected horizontally from the top of a tower of height h $$=$$ $$20$$ m with a speed u $$=$$ $$20$$ $$m/s$$ . Then the angle, measured with horizontal, at which the body will strike the ground is

Question

A body is projected horizontally from the top of a tower of height h $$=$$ $$20$$ m with a speed u $$=$$ $$20$$ $$m/s$$  . Then the angle, measured with horizontal, at which the body will strike the ground is

Infinity Learn · Accepted Answer

Just before striking the ground ' horizontal component of the velocity of the body vh $$=$$ $$20$$ $$m/s$$ Similarly vertical component of the velocity of the body vv $$=$$ $$2gh$$ $$=$$ $$2$$×$$10$$×$$20$$ $$m/s$$ $$=20$$ $$m/s$$ .Therfore angle between velocity vector and horizontal $$=$$ $$tan$$$$-1vvvh$$ $$=$$ $$tan$$$$-12020$$ $$=$$ $$450$$

A body is projected horizontally from the top of a tower of height h = 20 m with a speed u = 20 m/s . Then the angle, measured with horizontal, at which the body will strike the ground is

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