First slide

Projection Under uniform Acceleration

Question

A body is projected horizontally from the top of a tower. When the body strikes the ground, its velocity is V and the direction of motion makes $30^{0}$ with the horizontal. The velocity of projection is

Easy

A

$\frac{\sqrt{3} V}{2}$
B

$\frac{V}{\sqrt{3}}$
C

$\frac{V}{2}$
D

$\frac{2 V}{\sqrt{3}}$

Solution

if final velocity V and it makes an angle $30^{0}$ then $V \cos 30^{0} = V_{x} = i n i t i a l v e l o c i t y$
$V_{x}$ = $\frac{\sqrt{3} V}{2}$

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