A body is projected horizontally from the top of a tower with initial velocity 18 m s-1. It hits the ground at angle 45o . What is the vertical component of velocity when strikes the ground?

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9ms−1

92ms−1

18ms−1

182ms−1

answer is C.

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Detailed Solution

vcos⁡45∘=u=18ms−1⇒ v=182ms−1Vertical component vsin⁡45∘=182×12=18ms−1

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