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Q.

A body is projected horizontally from the top of a tower with a velocity of 10 ms-1. If it hits the ground at an angle of 45°, then the vertical component of velocity when it hits ground (in ms-1) is

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a

102

b

52

c

5

d

10

answer is D.

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Detailed Solution

The horizontal component of velocity,vx = u = 10ms-1Now,  tanθ=tan45°=vyvx=vy10⇒  vy = 10 ms-1
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A body is projected horizontally from the top of a tower with a velocity of 10 ms-1. If it hits the ground at an angle of 45°, then the vertical component of velocity when it hits ground (in ms-1) is