A body is projected horizontally from the top of a tower with a velocity of 10 ms-1. If it hits the ground at an angle of 45°, then the vertical component of velocity when it hits ground (in ms-1) is
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a
102
b
52
c
5
d
10
answer is D.
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Detailed Solution
The horizontal component of velocity,vx = u = 10ms-1Now, tanθ=tan45°=vyvx=vy10⇒ vy = 10 ms-1
A body is projected horizontally from the top of a tower with a velocity of 10 ms-1. If it hits the ground at an angle of 45°, then the vertical component of velocity when it hits ground (in ms-1) is