A body is projected at $$60o$$ with ground. It covers a horizontal distance of $$100$$ m. If the same body is projected at $$600$$ with vertical with same velocity, the new range is

Question

A body is projected at $$60o$$ with ground. It covers a horizontal distance of $$100$$ m. If the same body is projected at $$600$$ with vertical with same velocity, the new range is

Infinity Learn · Accepted Answer

Range, R $$=$$ $$u2$$ $$sin$$ $$2$$θgFor same v, R ∝ $$2$$θFor θ $$=$$ $$600$$ with horizontal, R is given as $$100$$ m when R ∝ $$sin$$ $$1200--------(i)For$$  θ $$=$$ $$600$$ with vertical        R' ∝ $$sin$$ $$2$$ (900-600)i$$.e., R' ∝ $$sin$$ $$600---------------(ii)Using$$ $$(i) and $$(ii)R$$'R $$=$$ $$sin$$ $$600sin$$ $$1200$$ $$=$$ $$11i$$.e., R' $$=$$ R $$=$$ $$100$$ m

A body is projected at $60^{o}$ with ground. It covers a horizontal distance of 100 m. If the same body is projected at $60^{0}$ with vertical with same velocity, the new range is

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A body is projected at 60o with ground. It covers a horizontal distance of 100 m. If the same body is projected at 600 with vertical with same velocity, the new range is

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Ready to Test Your Skills?

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A body is projected at $60^{o}$ with ground. It covers a horizontal distance of 100 m. If the same body is projected at $60^{0}$ with vertical with same velocity, the new range is