Questions
A body projected obliquely with velocity 19.6 m/s has its kinetic energy at the maximum height equal to 3 times its potential energy there. Its position after 1second of projection from the ground is (h = maximum height)
detailed solution
Correct option is D
KEat maximum height =3 PEat maximum height12mu2Cos2θ=3mgu2Sin2θ2gCos2θ=3Sin2θ hence θ=300y=uSinθt-12gt2 y=19.612×1-129.812=4.9 mh=u2Sin2θ2g=19.622×9.8×14=4.9mso y=hTalk to our academic expert!
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