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A body is projected up from the top of a tower AB of height 10 m, with a speed of 10 m/s making an angle of = 300 with horizontal. If g = 10 m/s2, the time after which it will strike the ground is
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Correct option is D
- 10 sin 300 ×t +12×10×t2 = 10 Solving , t = 2 sSimilar Questions
From the top of a tower of height 40 m a ball is projected upwards with a speed of 20 m/sec at an angle of elevation of 30o. Then the ratio of the total time taken by the ball to hit the ground to its time of flight (time taken to come back to the same elevation) is (take g = 10 m/sec2)
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