A body is projected up from the top of a tower AB of height 10 m, with a speed of 10 m/s making an angle of  = 300 with horizontal. If g = 10 m/s2, the time after which it will strike the ground is

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answer is D.

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Detailed Solution

- 10 sin 300 ×t +12×10×t2 = 10 Solving , t = 2 s

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