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Q.

A body is projected upwards with a velocity u. It passes through a certain point above the ground after t1. The time after which the body passes through the same point during the return journey is

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a

ug−t12

b

2ug−t1

c

3u2g−t1

d

3u2g2−t1

answer is B.

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Detailed Solution

Suppose v be the velocity attained by the body after time t1.Then v=u−gt1 …..(i)Let the body reach the same point at time t2. Now velocity will be downwards with same magnitude v. Then−v=u−gt2                             ......(ii) (i) −(ii)⇒2v=gt2−t1 or  t2−t1=2vg=2gu−gt1=2ug−t1
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