A body is projected upwards with a velocity u. It passes through a certain point above the ground after t1. The time after which the body passes through the same point during the return journey is
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a
ug−t12
b
2ug−t1
c
3u2g−t1
d
3u2g2−t1
answer is B.
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Detailed Solution
Suppose v be the velocity attained by the body after time t1.Then v=u−gt1 …..(i)Let the body reach the same point at time t2. Now velocity will be downwards with same magnitude v. Then−v=u−gt2 ......(ii) (i) −(ii)⇒2v=gt2−t1 or t2−t1=2vg=2gu−gt1=2ug−t1