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Q.

A body is projected vertically downwards with an initial velocity from a height of 10m on to a horizontal floor. During the impact it losses 50% of its energy and rebounds to the same height. The velocity of projection is   (g=9.8ms−2)

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a

14ms−1

b

28ms−1

c

9.8ms−1

d

19.6ms−1

answer is A.

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Detailed Solution

Ef=12Eimgh=1212mv2+mgh2mgh=12mv2+mghv=2×9.8×10=14ms−1
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