First slide

Vertical projection from ground

Question

A body is projected vertically up with u. Its velocity at half its maximum height is

Moderate

A

u/2
B

u /4
C

$\sqrt{2} u$
D

$\frac{u}{\sqrt{2}}$

Solution

$F r o m v^{2} - u^{2} = 2 a s v^{2} - u^{2} = - 2 g \frac{h}{2} v^{2} - u^{2} = - 2 g \frac{u^{2}}{4 g} v = \frac{u}{\sqrt{2}}$

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