A body is projected vertically upward with a velocity of 50 m/s . Then the ratio of distances  travelled in the first second of upward motion to first second of downward motion is (Take g =10 m/s2).

h1 = Distance travelled in the first second of upward motion = 50x1 - 1/2 x 10 x 12 = 45 mta = Time of ascent = u/g = 50/10 sec = 5 secSo at the end of 5 sec , The body is at the highest position and from that position it starts falling freely.: Distance travelled in the first second of downward motion , h2 = 1/2 x 10 x 12 m = 5m.:h1h2 = 45/5 = 9