A body is projected vertically upward with a velocity of 50 m/s . Then the ratio of distances travelled in the first second of upward motion to first second of downward motion is (Take g =10 ).
= Distance travelled in the first second of upward motion = 50x1 - 1/2 x 10 x = 45 m
= Time of ascent = u/g = 50/10 sec = 5 sec
So at the end of 5 sec , The body is at the highest position and from that position it starts falling freely
.: Distance travelled in the first second of downward motion , = 1/2 x 10 x m = 5m
.: = 45/5 = 9