First slide

Rectilinear Motion

Question

A body is projected vertically upwards and is reached to a vertical height of 20m and again reached the same point of projection. Then the distance travelled by the body is

Easy

A

20m
B

40m
C

10m
D

5m

Solution

Here the body covers the vertical height twice while moving up and moving down. Therefore the total length of the path covered or distance travelled is
$\begin{array}{l} S = 2 h \\ = 2 \times 20 = 40 m \end{array}$

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