First slide
Projection Under uniform Acceleration
Question

A body is projected with a certain speed at angles of projection of θ and 90 - θ. The maximum height attained in the two cases are 20 m and 10 m respectively. The maximum possible range is

Moderate
Solution

H1 = 20, H2 = 10
\large {H_1} + {H_2} = \frac{{{u^2}}}{{2g}} \Rightarrow {u^2} = 600
\large {R_{\max }} = \frac{{{u^2}}}{g} = \frac{{600}}{{10}} = 60m

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