Download the app

Projection Under uniform Acceleration

Question

A body is projected with a certain speed at angles of projection of θ and 90 - θ. The maximum height attained in the two cases are 20 m and 10 m respectively. The maximum possible range is

Moderate
Solution

H1 = 20, H2 = 10
\large {H_1} + {H_2} = \frac{{{u^2}}}{{2g}} \Rightarrow {u^2} = 600
\large {R_{\max }} = \frac{{{u^2}}}{g} = \frac{{600}}{{10}} = 60m



Talk to our academic expert!

+91

Are you a Sri Chaitanya student?



Similar Questions

A ball is projected obliquely with a velocity 49 ms–1 strikes the ground at a distance of  245 m from the point of projection. It remained in air for


phone icon
whats app icon