A body is projected with horizontal velocity 20 m/s from top of the tower of height ‘h’. It touches the ground with velocity 40 m/sec. Value of ‘h’ is: (g= 10 m/s2)

given initial velocity horizontally=u=20 m/s; final velocity=v=40 m/s; g=10 m/s2 equation of motion is     V2−U2=2gh substitute the given values in this equation, ⇒402−202=210h ⇒h=1600−40020=60m=height of the tower