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Q.

A body is projected with horizontal with a velocity 20 m/s from top of the tower. It touches the ground at angle ‘α’ with velocity of 40 m/sec. Value of  α is

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a

300

b

600

c

450

d

900

answer is B.

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Detailed Solution

Horizontal component of velocity is constant through out the motion given initial velocity u= ux=20 m/s final velocity =v=40 m/s   ux=vx 20=v cosα 20=40 Cos α ⇒12=Cos α cos600=Cos α ⇒α=600
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