First slide

Projection Under uniform Acceleration

Question

A body is projected with a velocity of (3i + 4j + 5k) m/s from the ground. Taking XY-plane as ground and Z axis as vertical, its range is (g = 10 m/s²)

Moderate

A

1 m
B

1.25 m
C

5 m
D

20 m

Solution

horizontal velocity $= \sqrt{3^{2} + 4^{2}} = 5 m / s$
vertical velocity = 5 m/s
$Range = Ucos θ \cdot \frac{2 Usin θ}{g} = \frac{5 \times 2 \times 5}{10} = 5 m$

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