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Q.

A body is projected with a velocity 206  m/s from a point P on an inclined plane having inclination 300 with horizontal making an angle of 450 with the plane. Then the time after which the body will strike the inclined plane is

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a

4 sec

b

6 sec

c

7 sec

d

8 sec

answer is D.

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Detailed Solution

Component of initial velocity normal to the inclined plane u = 206 sin 450 m/s = 203 m/s.Using the equation of time of flight we can write , T = 2ug cos 300= 2×20310 ×32s = 8 s
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