A body is projected with a velocity $$206$$ $$m/s$$ from a point P on an inclined plane having inclination $$300$$ with horizontal making an angle of $$450$$ with the plane. Then the time after which the body will strike the inclined plane is

Question

A body is projected with a velocity $$206$$  $$m/s$$ from a point P on an inclined plane having inclination $$300$$ with horizontal making an angle of $$450$$ with the plane. Then the time after which the body will strike the inclined plane is

Infinity Learn · Accepted Answer

Component of initial velocity normal to the inclined plane u $$=$$ $$206$$ $$sin$$ $$450$$ $$m/s$$ $$=$$ $$203$$ $$m/s$$.Using the equation of time of flight we can write , T $$=$$ $$2ug$$ $$cos$$ $$300=$$ $$2$$×$$20310$$ ×$$32s$$ $$=$$ $$8$$ s

A body is projected with a velocity $20 \sqrt{6} m / s$ from a point P on an inclined plane having inclination 30⁰ with horizontal making an angle of 45⁰with the plane. Then the time after which the body will strike the inclined plane is

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A body is projected with a velocity 206 m/s from a point P on an inclined plane having inclination 300 with horizontal making an angle of 450 with the plane. Then the time after which the body will strike the inclined plane is

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A body is projected with a velocity $20 \sqrt{6} m / s$ from a point P on an inclined plane having inclination 30⁰ with horizontal making an angle of 45⁰with the plane. Then the time after which the body will strike the inclined plane is