First slide

Projection Under uniform Acceleration

Question

A body is projected with velocity 24 ms^–1making an angle 30° with the horizontal. The vertical component of its velocity after 2 s is (g = 10 ms^–2)

Moderate

A

8 ms^-1 upward
B

8 ms^-1 downward
C

32 ms^-1 upward
D

32 ms^-1 downward

Solution

$\large {V_y} = u\sin \theta - gt = 24\sin {30^0} - 10 \times 2$

V_y= 12 – 20 = – 8ms^–1
–Ve sign indicates downwards

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