A body is projected with a velocity u. It passes through a certain point above the ground after t1 sec. The time after which the body passes through the same point during the return journey is
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a
ug−t12
b
2ug−t1
c
3u2g−t1
d
3u2g2−t1
answer is B.
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Detailed Solution
Let v be the velocity attained by the body after t1 sec.Then v = u -gt1We know that time taken to the reach the same pointt2=2vg=2gu−gt1or t2=2ug−t1