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Q.

A body is projected with a velocity u. It passes through a certain point above the ground after t1 sec. The time after which the body passes through the same point during the return journey is

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a

ug−t12

b

2ug−t1

c

3u2g−t1

d

3u2g2−t1

answer is B.

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Detailed Solution

Let v be the velocity attained by the body after t1 sec.Then v  = u  -gt1We know that time taken to the reach the same pointt2=2vg=2gu−gt1or t2=2ug−t1
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A body is projected with a velocity u. It passes through a certain point above the ground after t1 sec. The time after which the body passes through the same point during the return journey is