First slide

Projection Under uniform Acceleration

Question

A body is projected with velocity u such that its horizontal range and maximum vertical heights are same. The maximum heights is

Moderate

A

$\large \frac{{{u^2}}}{{2g}}$
B

$\frac{{{3u^2}}}{{4g}}$
C

$\frac{{{16u^2}}}{{17g}}$
D

$\frac{{{8u^2}}}{{17g}}$

Solution

R = H
Tanθ = 4H/R = 4

$\large \therefore H = \frac{{{u^2}{{\sin }^2}\theta }}{{2g}}$
$\large =\frac{u^2X(\frac{4}{\sqrt17})^2}{2g}$
$\large = \frac{{16{u^2}}}{{2g \times 17}} = \frac{{8{u^2}}}{{17g}}$

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