A body is released from a height H. At some position during its free fall, its kinetic energy is two times its potential energy. Then height of the body at that instant is
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a
2H3
b
H3
c
H4
d
3H4
answer is B.
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Detailed Solution
If the height is h, then KE+PE=mgH⇒2PE+PE=mgH⇒PE=mgH/3∴ mgh=mgH3⇒h=H3