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A body is released from a height R/2 above the surface of earth where R is the radius of earth. If g be the acceleration due to gravity on the surface of earth, velocity of the body just before it strikes the surface of earth is 

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a
gR2
b
12gR
c
2gR3
d
3gR4

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detailed solution

Correct option is C

Conserving energy, 12mV2+(−GMmR)=−GMm(R+R2)⇒V2=2GMR−4GM3R=2GM3R=23.GMR2R⇒V=2gR3


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