A body is released from the top of the tower of  height ‘h’. After 1 sec it is stopped and then instantaneously released.. What will be height after 3 sec  g=10m/s2

The distance covered in 1sec  S=12gt2 S=12(10)12 S=5m;The distance covered in next 2sec   S=12(10)32 S=45mTotal distances travelled down is 5+45=50m The height of stone from ground is  =h-50m