A body is released from the top of a tower of height H m. After 2 s, it is stopped and then instantaneously released. What will be its height after next 2 s?

Distance covered by the object in first 2 sh1=12gt2=12×10×22=20mSimilarly, distance covered by the object in next 2 s will also be 20 m, hence the required height = H-20-20= H-40 m