A body at rest breaks up into 3 parts. If 2 parts having equal masses fly off perpendicularly each after with a velocity of 12m/s, then the velocity of the third part which has 3 times mass of each part is
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a
42 m/s at an angle of 45o from each body
b
242 m/s at an angle of 135o from each body
c
62 m/s at 135o from each body
d
42 m/s at 135o from each body
answer is D.
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Detailed Solution
The momentum of third part will be equal and opposite to the resultant of momentum of rest two equal parts let V is the velocity of third part. By the conservation of linear momentum 3m×V=m×122 ⇒V=42 m/s