A body is at rest under the action of three forces, two of which are $$F1$$→ $$=$$ $$4i^$$, $$F2$$→ $$=$$ $$6j^$$, the third force is

Correct option is 4−4i^−6j^

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A body is at rest under the action of three forces, two of which are $\vec{F_{1}} = 4 \hat{i}$ , $\vec{F_{2}} = 6 \hat{j}$ , the third force is

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4i^+6j^

4i^−6j^

−4i^+6j^

−4i^−6j^

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detailed solution

Correct option is D

F1→+F2→+F3→ =0 ⇒4i^+6j^+F3→ =0∴ F3→ = −4i^−6j^

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A body is at rest under the action of three forces, two of which are F1→ = 4i^, F2→ = 6j^, the third force is

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A body is at rest under the action of three forces, two of which are $\vec{F_{1}} = 4 \hat{i}$ , $\vec{F_{2}} = 6 \hat{j}$ , the third force is