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Q.

A body is at rest at x=0. At t=0, it starts moving in the positive X -direction with a constant acceleration. At the same instant, another body passes through x=0 moving in the positive X -direction with a constant speed. The position of the first body is given by x1(t) after time t and that of the second body by x2(t) after the same time interval. Which of the following graphs correctly describes x2-x1 as a function of time?

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a

b

c

d

answer is C.

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Detailed Solution

x2-x1=vt-12at2x2-x1 is zero at t=0and t=2vaFor t<2va,x2-x1 is positive and after that it is negative.Further, x2-x1 versus t graph is a parabola.
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A body is at rest at x=0. At t=0, it starts moving in the positive X -direction with a constant acceleration. At the same instant, another body passes through x=0 moving in the positive X -direction with a constant speed. The position of the first body is given by x1(t) after time t and that of the second body by x2(t) after the same time interval. Which of the following graphs correctly describes x2-x1 as a function of time?