First slide

Simple harmonic motion

Question

A body in SHM has a maximum acceleration of 24 m s^–2 and maximum velocity 16 m s^–1. The amplitude of SHM is nearly

Moderate

A

4 m
B

8 m
C

9 m
D

11 m

Solution

$\begin{array}{l} a_{max} = A ω^{2} = 24 \\ V_{max} = A ω = 16 \\ ∴ ω = \frac{24}{16} = \frac{3}{2} ∴ A = \frac{16}{ω} = \frac{16}{(3 / 2)} = \frac{32}{3} m . \end{array}$

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