First slide

Simple hormonic motion

Question

For a body in S.H.M the velocity is given by the relation v = $\large \sqrt {144 - 16{x^2}}$ m/sec. The maximum acceleration is

Easy

A

12 m/sec²
B

16 m /sec²
C

36 m/sec²
D

48 m/sec²

Solution

$\large v\, = \,\sqrt {144 - 16{x^2}} \, = \,\sqrt {9 \times 16 - 16{x^2}}$
$\large v\, = \,4\sqrt {{3^2} - {x^2}} \, = \,w\sqrt {{A^2} - {x^2}}$
$\large w\, = \,4rad/\sec ;\,A\, = 3m$
$\large {a_{\max }}\, = \,{\omega ^2}A\, = \,{\left( 4 \right)^2}3\, = \,48m/{s^2}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App