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Friction on inclined plane of angle more than angle of repose

Question

A body is sliding down a rough inclined plane. The coefficient of friction between the body and the plane is 0.5. The ratio of the net force required for the body to slide down and the normal reaction on the body is 1 : 2. Then the angle of the inclined plane is

Moderate

A

15°
B

30°
C

45°
D

60°

Solution

$F = mg (\sin θ - μ_{k} \cos θ), N = mgcos θ$

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