A body starts from rest and falls vertically from a height of 19.6 metre. If g = 9.8 ms-2, then the distance travelled by the body in the last 0.1 seconds of its motion is

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1.9 metre

0.049 metre

17.7 metre

19. 6 metre

answer is A.

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Detailed Solution

Time of free fall =2hg=2×19.69.8=2secdistance travelled in(2−0.1)sec=1.9sec is 12s(1.9)2distance travelled in last 0.1 sec.12g(2)2−12g(1.9)2=1.95m

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