A body starts from rest and moves with constant acceleration for t second. It travels a distance x1 in first half of time and x2 in next half of time, then

a = constantLet A be the original point.From equation of motion,                        x=ut+12at2=12at2                              (∵ u = 0)For point C,    x1=12a(t/2)2⇒x1=18at2Distance travelled by the body in t second is               x1+x2=12a(t)2=4x1                     x2 = 4x1 - x1 = 3x1