A body starts from rest and travels a distance S with uniform acceleration, then moves uniformly a distance 2S and finally comes to rest after moving further 5S under uniform retardation. The ratio of the average velocity to maximum velocity is
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a
2/5
b
3/5
c
4/7
d
5/7
answer is C.
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Detailed Solution
Graphically, the area of v-t curve represents displacement: S=12vmaxt1 or t1=2Svmax2S=vmaxt2 or t2=2Svmax5S=12vmaxt3 or t3=10Svmaxvav = Total displacement Total time =S+2S+5S2Svmax+2Svmax+10Svmaxvavvmax=8S14S=47.Alternative: vavvmax= Total displacement 2 Total displacement during acceleration and retardation + Displacement during uniform velocity vavvmax=8S2(S+5S)+2S=814=47